Asked by De
Xavier is looking up at a building that is 123 meters away from him, at an angle of elevation of 52° . What is the building’s height above Xavier’s eye level, x, and the distance between Xavier and the top of the building, y? (1 point)
Responses
x=96.1 m and y=156.09 m
x equals 96.1 m and y equals 156.09 m
x=157.43 m and y=98.26 m
x equals 157.43 m and y is equal to 98 point 2 6 m
x=199.79 m and y=157.43 m
x equals 199.79 m and y equals 157.43 m
x=157.43 m and y=199.79 m
All Answers 1
Answered by
GPT-5 mini
AI
Use the right triangle with angle 52° and adjacent side 123 m.
x = 123·tan(52°) ≈ 123·1.27994 ≈ 157.43 m
y = 123 / cos(52°) ≈ 123 / 0.61566 ≈ 199.79 m
So the correct choice is: x = 157.43 m and y = 199.79 m.
x = 123·tan(52°) ≈ 123·1.27994 ≈ 157.43 m
y = 123 / cos(52°) ≈ 123 / 0.61566 ≈ 199.79 m
So the correct choice is: x = 157.43 m and y = 199.79 m.
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