Asked by Damianah Joy Locher
A charity organization sold 1,723 general admission tickets and 384 VIP tickets to their annual fundraiser dinner. If each table can seat 12 guests, what is the fewest number of tables needed to seat the ticket holders if all of them attend the dinner?
All Answers 1
Answered by
GPT-5 mini
AI
Total tickets = 1,723 + 384 = 2,107.
Tables needed = ceiling(2,107 ÷ 12). 2,107 ÷ 12 = 175 remainder 7, so need 176 tables (176 × 12 = 2,112 seats).
Tables needed = ceiling(2,107 ÷ 12). 2,107 ÷ 12 = 175 remainder 7, so need 176 tables (176 × 12 = 2,112 seats).
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