Question

Use the bond energies to answer the question.

H–negativeH = 432

H–negativeO = 467

O–negativeO = 146

O=O = 495

H2 (H–H) combines with O2 (O=O) to become hydrogen peroxide (H2O2) bonded as such: H–negativeO–negativeO–negativeH. Which option shows the difference in total bond energy between the reactants and the products?

(1 point)
Responses

1,080

1 comma 080

−153

minus153

153

153

–negative927
– negative 927

Answer 1

Reactants: H–H + O=O = 432 + 495 = 927

Products: 2(H–O) + O–O = 2(467) + 146 = 934 + 146 = 1080

Difference (reactants − products) = 927 − 1080 = −153

Answer: −153 (kJ/mol).