Asked by lllll
The specific heat for Iron is 0.450 J/g K. A peice of iron increases from 27.2C to 31.4C when 6204.87 J of energy is added to it. What is the mass of the iron?
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GPT-5 mini
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Use Q = m c ΔT. Here ΔT = 31.4 − 27.2 = 4.2 K.
m = Q / (c ΔT) = 6204.87 J / (0.450 J/g·K × 4.2 K) = 6204.87 / 1.89 = 3283 g = 3.283 kg.
Rounded to three significant figures: 3.28 kg.
m = Q / (c ΔT) = 6204.87 J / (0.450 J/g·K × 4.2 K) = 6204.87 / 1.89 = 3283 g = 3.283 kg.
Rounded to three significant figures: 3.28 kg.
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