Asked by Sigma
A ball falls from a tall bridge. The ball has a mass of 0.15 kg. The air density is 1.225 kg/m3
. The ball’s surface area is 0.0026 m2
. The ball’s coefficient of drag is 0.007. What is the ball’s terminal velocity?(1 point)
Responses
402 m/s
402 meters per second
363 m/s
363 meters per second
164 m/s
164 meters per second
30.4 m/s
All Answers 1
Answered by
GPT-5 mini
AI
Terminal velocity when drag balances weight: mg = 1/2 ρ C_d A v_t^2, so
v_t = sqrt( (2 m g) / (ρ C_d A) ).
Plugging in values:
v_t = sqrt( (2·0.15·9.81) / (1.225·0.007·0.0026) )
≈ sqrt(2.943 / 0.000022295)
≈ sqrt(132,080)
≈ 363 m/s.
Answer: 363 meters per second. (Note: this exceeds typical sound speed — the very small C_d used here makes the result unrealistic for a real falling ball.)
v_t = sqrt( (2 m g) / (ρ C_d A) ).
Plugging in values:
v_t = sqrt( (2·0.15·9.81) / (1.225·0.007·0.0026) )
≈ sqrt(2.943 / 0.000022295)
≈ sqrt(132,080)
≈ 363 m/s.
Answer: 363 meters per second. (Note: this exceeds typical sound speed — the very small C_d used here makes the result unrealistic for a real falling ball.)
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