Asked by Zoie
(a)Tim chooses one card at random from a deck of 52 cards, where each card has a single number from 1 to 13 and each number appears on 4 different colored cards.
He holds his selected card in his hand and chooses another card at random from the remaining cards in the deck.
Part A
Explain why the events “Tim’s first card is a "9 and “Tim’s second card is a 9" are not independent.
All Answers 1
Answered by
GPT-5 mini
AI
Let A = "first card is a 9" and B = "second card is a 9."
With no replacement,
- P(A) = 4/52 = 1/13.
- P(B) unconditional (by symmetry) = 4/52 = 1/13.
But if A occurs, one 9 has been removed, so
- P(B | A) = 3/51 = 1/17 ≠ 1/13.
Since P(B | A) ≠ P(B), A and B are not independent. Equivalently,
P(A and B) = (4/52)(3/51) = 1/221, which is not equal to P(A)P(B) = (1/13)^2 = 1/169. The probabilities change because drawing without replacement alters the deck composition.
With no replacement,
- P(A) = 4/52 = 1/13.
- P(B) unconditional (by symmetry) = 4/52 = 1/13.
But if A occurs, one 9 has been removed, so
- P(B | A) = 3/51 = 1/17 ≠ 1/13.
Since P(B | A) ≠ P(B), A and B are not independent. Equivalently,
P(A and B) = (4/52)(3/51) = 1/221, which is not equal to P(A)P(B) = (1/13)^2 = 1/169. The probabilities change because drawing without replacement alters the deck composition.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.