Question

A spring with Elastic Potential Energy of 256 J and is extended 50 m. What is the spring constant of the spring? ential energy
stored?

Use Formula: PEelastic = KX2 / 2 K is spring contstant (n/m) , x is distance (m)

Answer 1

Use PE = 1/2 k x^2. Rearranged: k = 2·PE / x^2.

Plugging in PE = 256 J and x = 50 m:
k = 2·256 / (50^2) = 512 / 2500 = 0.2048 N/m.

So the spring constant is 0.205 N/m (≈2.05×10^-1 N/m).

(If the extension was meant to be 50 cm = 0.50 m, then k = 2·256 / (0.5^2) = 2048 N/m.)