Question

A spring with spring constant 55 N/m is extended 3 m. What is the elastic potential energy
stored?

Use Formula: PEelastic = KX2 / 2 K is spring contstant (n/m) , x is distance (m)

Answer 1

PE = 1/2 k x^2 = 1/2 (55 N/m) (3 m)^2 = 1/2 · 55 · 9 = 247.5 J

So the elastic potential energy stored is 247.5 J (≈248 J).