Asked by …
Weston. How dow news
Predict: Which person will do more work:
Procedures
1. Assign each person a table group role.
2. Select one person with a greater mass and one with a lesser mass
3. Person 1 walks/runs the stairs the full distance 4.5 meters for calculations.
Which person will produce the most power:
S, After each trial the timer will report the time to the recorder. The record will write the time in the table below.
6. Repeat this 3 times for person, walk/tun the stairs at varving their soced
7. Once person 1 has gone 3 times, person 2 have their turn repeating the process 3 times as well
8. Once done return to class to perform calculations and respond to concept questions, work as a group but everyone complete this document themself for credit
Rocoed
Calculate after
Record data
Calculate after
Wate
(kg)
(pounds+2)
Distance
Time (s)
Weight (N)
ork!
done
Power output
pou nose
Distance (m)
Time
Weight
done
Power output
slow
50
4.5 m
645
490.5 220128
134.34
45
4.5 m
2559
4g4S 1,93055 8939
quickly
50
4.5 m
3.4
490s 220725
168.74
45
4.5 m
44145
4986.53
11845
fast
50
4.5 m
10.49
490.5 220125 210.42
45
286 44145/198655 15447
Average
(add them up + 3)
490.S 2,20728 1712
Average
(add them up + 3)
4414511.9865 117.44
Analyze Your Data -Calculations
SHOW ALL Math processes equation, su#s, solve with units
1. Calulate the weight of each object and record it into your data chart. Formula:
Person 2
2. Calculate the work done for each object and record it in the data table. Formula:
Person 1: Triala
Trial 2
Trial 3
Person 2: Trial 1
Trial 2
Trial 3
Avg work :
3. Calculate the Power of each object and record it in the data table. Formula:
Person 1: Triald
Trial 2
Trial 3
Person 2: Triali
Trial 2
Trial 3
Ays power
All Answers 1
Answered by
GPT-5 mini
AI
I can finish all the “show all work” calculations, but a few of your recorded times are hard to read. Before I do every trial, please confirm the three times for each person (slow / medium / fast). Right now I can reliably read the masses (50 kg and 45 kg) and the distance (4.5 m). If those are correct, I’ll complete the rest once you confirm the three times per person.
While you confirm, here’s the clear step-by-step method and the calculations that don’t depend on ambiguous times (with g = 9.81 m/s^2).
1) Prediction (short)
- Which person will do more work? The person with the greater mass will do more work because gravitational work = m g h and m is larger.
- Which person will produce the most power? Power depends on time: the person who takes the least time (runs up fastest) will produce the most average power (for the same height). So heavier person does more work; the faster person produces more power.
2) Formulas (showing units)
- Weight (force): Wt = m · g
units: kg · (m/s^2) = N (newtons)
- Work done to lift body up stairs height h: Work = Wt · h = m · g · h
units: N · m = J (joules)
- Average power for a trial: P = Work / t
units: J / s = W (watts)
3) Given values (confirm if correct)
- Person A mass = 50.0 kg
- Person B mass = 45.0 kg
- Distance (vertical height climbed) h = 4.50 m
- g = 9.81 m/s^2
4) Weight (force) calculations (showing full math)
- Person A weight:
Wt_A = m_A · g = 50.0 kg × 9.81 m/s^2 = 490.5 N
- Person B weight:
Wt_B = m_B · g = 45.0 kg × 9.81 m/s^2 = 441.45 N
5) Work done (energy) for climbing h = 4.50 m (full math)
- Person A:
Work_A = Wt_A · h = 490.5 N × 4.50 m
= 2,207.25 J
- Person B:
Work_B = Wt_B · h = 441.45 N × 4.50 m
= 1,986.525 J
(Conclusion from these: Person A (50 kg) does 2,207.25 J; Person B does 1,986.525 J. Person A does more work because of larger mass.)
6) Power — example trial calculations (showing full math)
When you give me the actual times, I will compute these the same way. Example using times I can clearly read from your notes:
Example Trial 1 for Person A (if t = 10.49 s)
- P_A1 = Work_A / t = 2,207.25 J / 10.49 s = 210.42 W
(units: J/s = W)
Example Trial 2 for Person A (if t = 3.40 s)
- P_A2 = 2,207.25 J / 3.40 s = 649.78 W
Example Trial 3 for Person A (if t = 6.45 s)
- P_A3 = 2,207.25 J / 6.45 s = 342.87 W
Example for Person B (use Work_B = 1,986.525 J). If, for instance, a trial time t = 4.50 s:
- P_B = 1,986.525 J / 4.50 s = 441.45 W
7) Averages
- Average work per person: because all three trials use the same mass and same height, the work per trial is identical for that person; average work = same value (e.g., Person A average work = 2,207.25 J).
- Average power per person: P_avg = (P_trial1 + P_trial2 + P_trial3) / 3
(compute after you confirm the three times for each person).
8) What I need from you to finish everything with full shown math
Please type the three times (in seconds) for each person, clearly labeled, e.g.:
- Person A (50 kg): t1 = __ s, t2 = __ s, t3 = __ s
- Person B (45 kg): t1 = __ s, t2 = __ s, t3 = __ s
Once you send those six times I will:
- compute P for every trial (showing every step and units),
- compute the average power for each person,
- fill in the table values,
- state clearly which person did more work and which produced more power (with the numeric evidence).
If you want, I can also format the final results into a clean table for your document.
While you confirm, here’s the clear step-by-step method and the calculations that don’t depend on ambiguous times (with g = 9.81 m/s^2).
1) Prediction (short)
- Which person will do more work? The person with the greater mass will do more work because gravitational work = m g h and m is larger.
- Which person will produce the most power? Power depends on time: the person who takes the least time (runs up fastest) will produce the most average power (for the same height). So heavier person does more work; the faster person produces more power.
2) Formulas (showing units)
- Weight (force): Wt = m · g
units: kg · (m/s^2) = N (newtons)
- Work done to lift body up stairs height h: Work = Wt · h = m · g · h
units: N · m = J (joules)
- Average power for a trial: P = Work / t
units: J / s = W (watts)
3) Given values (confirm if correct)
- Person A mass = 50.0 kg
- Person B mass = 45.0 kg
- Distance (vertical height climbed) h = 4.50 m
- g = 9.81 m/s^2
4) Weight (force) calculations (showing full math)
- Person A weight:
Wt_A = m_A · g = 50.0 kg × 9.81 m/s^2 = 490.5 N
- Person B weight:
Wt_B = m_B · g = 45.0 kg × 9.81 m/s^2 = 441.45 N
5) Work done (energy) for climbing h = 4.50 m (full math)
- Person A:
Work_A = Wt_A · h = 490.5 N × 4.50 m
= 2,207.25 J
- Person B:
Work_B = Wt_B · h = 441.45 N × 4.50 m
= 1,986.525 J
(Conclusion from these: Person A (50 kg) does 2,207.25 J; Person B does 1,986.525 J. Person A does more work because of larger mass.)
6) Power — example trial calculations (showing full math)
When you give me the actual times, I will compute these the same way. Example using times I can clearly read from your notes:
Example Trial 1 for Person A (if t = 10.49 s)
- P_A1 = Work_A / t = 2,207.25 J / 10.49 s = 210.42 W
(units: J/s = W)
Example Trial 2 for Person A (if t = 3.40 s)
- P_A2 = 2,207.25 J / 3.40 s = 649.78 W
Example Trial 3 for Person A (if t = 6.45 s)
- P_A3 = 2,207.25 J / 6.45 s = 342.87 W
Example for Person B (use Work_B = 1,986.525 J). If, for instance, a trial time t = 4.50 s:
- P_B = 1,986.525 J / 4.50 s = 441.45 W
7) Averages
- Average work per person: because all three trials use the same mass and same height, the work per trial is identical for that person; average work = same value (e.g., Person A average work = 2,207.25 J).
- Average power per person: P_avg = (P_trial1 + P_trial2 + P_trial3) / 3
(compute after you confirm the three times for each person).
8) What I need from you to finish everything with full shown math
Please type the three times (in seconds) for each person, clearly labeled, e.g.:
- Person A (50 kg): t1 = __ s, t2 = __ s, t3 = __ s
- Person B (45 kg): t1 = __ s, t2 = __ s, t3 = __ s
Once you send those six times I will:
- compute P for every trial (showing every step and units),
- compute the average power for each person,
- fill in the table values,
- state clearly which person did more work and which produced more power (with the numeric evidence).
If you want, I can also format the final results into a clean table for your document.
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