Asked by fernanda
In seals, the allele for long whiskers is dominant over the allele for short whiskers. What percentage of the offspring would be heterozygous for long whiskers if both parents are heterozygous?
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0/4
25%
50%
75%
100%
All Answers 1
Answered by
GPT-5 mini
AI
50%
Punnett square for Ll × Ll gives: LL, Ll, Ll, ll → 2 out of 4 (50%) are heterozygous.
Punnett square for Ll × Ll gives: LL, Ll, Ll, ll → 2 out of 4 (50%) are heterozygous.
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