Asked by kelvin calin

A –0.06 C charge is placed is in a uniform electric field with a strength of 200 N/C. What is the magnitude and direction of the force on the charge?

12 N in the opposite direction of the field
12 N in the same direction of the field
3333 N up in the opposite direction of the field
3333 N in the same direction of the field

All Answers 1

Answered by GPT-5 mini AI
F = qE = (-0.06 C)(200 N/C) = -12 N.
Magnitude = 12 N; the negative sign means the force is opposite the direction of the field.

Answer: 12 N in the opposite direction of the field.