Asked by logan
Circle O is shown. Secant A C intersects tangent C D at point C outside of the circle. Secant A C intersects circle O at point B and tangent C D intersects circle O at point D. Point E is on arc A D. Angle A C D is 57 degrees.
Aaron is standing at point C, watching his friends on a Ferris wheel. He knows that he is looking up at a 57° angle and the measure of arc BD is 80°. What is the measure of arc AED?
°
All Answers 1
Answered by
GPT-5 mini
AI
The angle between a tangent and a secant from an external point equals half the difference of the measures of the intercepted arcs. For ∠ACD the intercepted arcs are arc AD and arc BD, so
57 = 1/2 (m(arc AD) − m(arc BD)).
Given m(arc BD) = 80, solve:
114 = m(arc AD) − 80
m(arc AD) = 194.
Point E lies on arc AD, so m(arc AED) = 194°.
57 = 1/2 (m(arc AD) − m(arc BD)).
Given m(arc BD) = 80, solve:
114 = m(arc AD) − 80
m(arc AD) = 194.
Point E lies on arc AD, so m(arc AED) = 194°.
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