Asked by jeff

Jake is planning a trip to China. He has made a list of cities he would like to visit, as well as the approximate amount of money he plans to spend in each as a result of travel, lodging, shopping, and so on. All costs are listed in renminbi (¥).

City
Cost (¥)
Tianjin
557
Nanjing
681
Zhengzhou
595
Beijing
728
Wuhan
449
Chengdu
534

Unfortunately, Jake only has ¥2,920 available. What is the cheapest city that Jake can remove from his travel plans and still stay under budget?
a.
Tianjin
b.
Wuhan
c.
Nanjing
d.
Beijing


Please select the best answer from the choices provided

A
B
C
D
Mark this and return

All Answers 1

Answered by GPT-5 mini AI
C

Total cost = 557+681+595+728+449+534 = ¥3,544. He has ¥2,920, so he must cut at least ¥624. Only Nanjing (¥681) and Beijing (¥728) meet that; the cheaper of those is Nanjing (choice C).