Asked by Ian
Given triangle LMN and triangle VTU, how might the AA similarity theorem be used to prove triangle LMN - triangle VTU. A. Show angle L = angle V and angle M = angle T. B. Show angle L = angle V and angle M = angle U. C. Show LM : VT=MN : TU. D. Show angle L + angle M + angle N = angle V + angle T + angle U = 180.
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Answer: A.
Reason: AA (angle-angle) similarity requires two pairs of corresponding angles to be equal. For LMN ~ VTU the correspondence is L↔V, M↔T, N↔U, so you can show angle L = angle V and angle M = angle T (or angle L = angle V and angle N = angle U).
B mismatches the correspondence, C uses side ratios (not AA), and D merely states the angle-sum property (true for each triangle but not a similarity test).
Reason: AA (angle-angle) similarity requires two pairs of corresponding angles to be equal. For LMN ~ VTU the correspondence is L↔V, M↔T, N↔U, so you can show angle L = angle V and angle M = angle T (or angle L = angle V and angle N = angle U).
B mismatches the correspondence, C uses side ratios (not AA), and D merely states the angle-sum property (true for each triangle but not a similarity test).
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