Question

On a coordinate plane, a circle has a center at (0, negative 3).
What is the equation of the circle shown in the graph?

(x – 3)2 + y2 = 4
(x + 3)² + y² = 2
x² + (y + 3)² = 4
x² + (y – 3)² = 2

Answer 1

Center (0,-3) gives equation in form x^2 + (y+3)^2 = r^2. The only choice with that center is x^2 + (y + 3)^2 = 4 (radius 2).