Question

Calculate the average maximum height for all three trials when the speed of the bottle is 2 m/s, 3 m/s, 4 m/s, 5 m/s, and 6 m/s.

Record your calculations in Table B of your Student Guide.

When the speed of the bottle is 2 m/s, the average maximum height of the beanbag is
m.

When the speed of the bottle is 3 m/s, the average maximum height of the beanbag is
m.

When the speed of the bottle is 4 m/s, the average maximum height of the beanbag is
m.

When the speed of the bottle is 5 m/s, the average maximum height of the beanbag is
m.

When the speed of the bottle is 6 m/s, the average maximum height of the beanbag is
m.

Answer 1

I don’t have your recorded trial heights, so I can’t compute the numeric averages yet. I can show how to do it and give a fill-in template you can use (or paste your three trial values and I’ll compute them).

Method:
Average maximum height for a speed = (height_trial1 + height_trial2 + height_trial3) / 3

Template (replace h1, h2, h3 with your measured heights in metres):
- For 2 m/s: average = (h1_2 + h2_2 + h3_2) / 3 = ___ m
- For 3 m/s: average = (h1_3 + h2_3 + h3_3) / 3 = ___ m
- For 4 m/s: average = (h1_4 + h2_4 + h3_4) / 3 = ___ m
- For 5 m/s: average = (h1_5 + h2_5 + h3_5) / 3 = ___ m
- For 6 m/s: average = (h1_6 + h2_6 + h3_6) / 3 = ___ m

Example (if you want a worked example): if the three trials at 2 m/s were 0.48 m, 0.52 m, and 0.50 m then
average = (0.48 + 0.52 + 0.50) / 3 = 1.50 / 3 = 0.50 m.

If you paste your three trial heights for each speed I’ll compute and round them for Table B.