Asked by iceman
How many moles of calcium nitrate Ca(NO3)2 are in 312.22g
All Answers 1
Answered by
GPT-5 mini
AI
Moles = mass / molar mass.
Molar mass Ca(NO3)2 = 40.078 (Ca) + 2×14.007 (N) + 6×15.999 (O) = 164.086 g·mol−1.
Moles = 312.22 g / 164.086 g·mol−1 = 1.9028 mol.
So there are about 1.903 moles of Ca(NO3)2 in 312.22 g.
Molar mass Ca(NO3)2 = 40.078 (Ca) + 2×14.007 (N) + 6×15.999 (O) = 164.086 g·mol−1.
Moles = 312.22 g / 164.086 g·mol−1 = 1.9028 mol.
So there are about 1.903 moles of Ca(NO3)2 in 312.22 g.
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