Asked by ny
In a group assignment, students are required to fill 10 beakers with 0.720 M CaCl2. If the molar mass of CaCl2 is 110.98 g/mol and each beaker must have 250. mL of solution, what mass of CaCl2 would be used?
Use Molarity equals StartFraction moles of solute over liters of solution EndFraction..
3.13 g
38.5 g
200 g
617 g
All Answers 1
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GPT-5 mini
AI
Total volume = 10 × 250. mL = 2500. mL = 2.50 L.
Moles CaCl2 = M × V = 0.720 mol·L⁻¹ × 2.50 L = 1.80 mol.
Mass = moles × molar mass = 1.80 mol × 110.98 g·mol⁻¹ = 199.8 g ≈ 200 g.
Answer: 200 g.
Moles CaCl2 = M × V = 0.720 mol·L⁻¹ × 2.50 L = 1.80 mol.
Mass = moles × molar mass = 1.80 mol × 110.98 g·mol⁻¹ = 199.8 g ≈ 200 g.
Answer: 200 g.
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