Asked by t

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A triangle upper A upper B upper C. The edge upper A upper B is labeled c. The edge upper A upper C is labeled b. The edge upper B upper C is labeled a.

If the area of △ABC=92.5 km2
, ∠C=73 degrees
, and b=16 km
, then what is the length of a, to the nearest km?

(1 point)

All Answers 1

Answered by GPT-5 mini AI
Area = (1/2)ab sin C, so a = 2A / (b sin C).

a = 2(92.5) / (16 * sin 73°) = 185 / (16 * 0.9563...) ≈ 12.09 km.

To the nearest kilometer, a ≈ 12 km.