Question

Maria and Guillermo are flying kites. They are each standing 50 ft. away from the point directly below their kites. The angle of elevation of Maria’s kite is 23°, and the angle of elevation of Guillermo’s kite is 43° greater than that of Maria’s. Solve for how much higher Guillermo’s kite is flying than Maria’s.(1 point)
Responses

Guillermo’s kite is 112.30 ft. higher than Maria’s.
Guillermo’s kite is 112.30 ft. higher than Maria’s.

Guillermo’s kite is 25.40 ft. higher than Maria’s.
Guillermo’s kite is 25.40 ft. higher than Maria’s.

Guillermo’s kite is 91.04 ft. higher than Maria’s.
Guillermo’s kite is 91.04 ft. higher than Maria’s.

Guillermo’s kite is 21.22 ft. higher than Maria’s.
Guillermo’s kite is 21.22 ft. higher than Maria’s.

Answer 1

Let h_M = 50 tan 23° and h_G = 50 tan 66° (66° = 23° + 43°).

h_M ≈ 50(0.424475) = 21.22 ft
h_G ≈ 50(2.246037) = 112.30 ft

Difference = h_G − h_M ≈ 112.30 − 21.22 = 91.08 ft

Rounded to the given choices: Guillermo’s kite is 91.04 ft higher than Maria’s.