Asked by Drizzy Epstien
1. Prove parallel lines have the same slope. Use lines r and s. Line s is a vertical translation of line r.
(a) A translation is a rigid transformation. How does this statement support line s being parallel to line r?
(b) Write an expression for the slope of line r.
(c) Write an expression for the slope of line s.
(d) Line q is a vertical translation of line s 3 units down. is the image of . What are the coordinates of ?
All Answers 1
Answered by
GPT-5 mini
AI
Let r be a line and s be a vertical translation of r by k units (so every point (x,y) on r corresponds to (x,y+k) on s).
(a) A translation is a rigid motion: it preserves distances and angles. In particular it preserves the direction of a line. If s is the image of r under a translation, then r and s have the same direction and therefore are parallel.
(b) Take two distinct points on r, say A(x1,y1) and B(x2,y2). The slope of r is
m_r = (y2 − y1)/(x2 − x1).
(c) Under the vertical translation by k, A and B map to A'(x1,y1+k) and B'(x2,y2+k), points on s. The slope of s is
m_s = ((y2+k) − (y1+k))/(x2 − x1) = (y2 − y1)/(x2 − x1) = m_r.
Thus the slopes are equal. (If r is vertical, its slope is undefined; a vertical translation keeps x-coordinates the same so s is also vertical — both have the same (undefined) slope.)
(d) A vertical translation 3 units down sends any point (x,y) to (x,y−3). So the image of a point (x,y) on s under this translation is (x, y−3). (If you have a specific point, substitute its coordinates to get the numeric image.)
(a) A translation is a rigid motion: it preserves distances and angles. In particular it preserves the direction of a line. If s is the image of r under a translation, then r and s have the same direction and therefore are parallel.
(b) Take two distinct points on r, say A(x1,y1) and B(x2,y2). The slope of r is
m_r = (y2 − y1)/(x2 − x1).
(c) Under the vertical translation by k, A and B map to A'(x1,y1+k) and B'(x2,y2+k), points on s. The slope of s is
m_s = ((y2+k) − (y1+k))/(x2 − x1) = (y2 − y1)/(x2 − x1) = m_r.
Thus the slopes are equal. (If r is vertical, its slope is undefined; a vertical translation keeps x-coordinates the same so s is also vertical — both have the same (undefined) slope.)
(d) A vertical translation 3 units down sends any point (x,y) to (x,y−3). So the image of a point (x,y) on s under this translation is (x, y−3). (If you have a specific point, substitute its coordinates to get the numeric image.)
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.