Question

Use the image to answer the question.

A coordinate plane's x-axis ranges from 0 to 8 and its y-axis ranges from negative 4 to 2, both by 1-unit increments. A concave up parabola is drawn passing through the 1st and 4th quadrants.
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What is the equation for the function in the graph?

(1 point)
Responses

y=−(x−3)2−5

y equals negative left parenthesis x minus 3 right parenthesis squared minus 5

y=(x−5)2−3

y equals left parenthesis x minus 5 right parenthesis squared minus 3

y=3(x−5)2−3

y equals 3 left parenthesis x minus 5 right parenthesis squared minus 3

y=2(x−5)2−3

y equals 2 left parenthesis x minus 5 right parenthesis squared minus 3

Answer 1

y = 2(x − 5)^2 − 3

Reason: The vertex from the graph is (5, −3), so y = a(x − 5)^2 − 3. The graph also passes through (4, −1). Plugging in gives −1 = a(4 − 5)^2 − 3 → −1 = a(1) − 3 → a = 2.