Asked by Zephyr Benedict
A cone has a diameter of 12 inches, a height of 14 inches, and a slant height 15 inches. What is the height of the right circular cone?
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Those three numbers are inconsistent for a right circular cone. If the diameter is 12, the radius is r = 6, and for a right cone the slant height l, radius r, and height h satisfy l^2 = r^2 + h^2. With l = 15 and r = 6,
h = sqrt(15^2 − 6^2) = sqrt(225 − 36) = sqrt(189) = 3√21 ≈ 13.747.
So a right circular cone with diameter 12 and slant height 15 has height 3√21 (not 14). If you meant something else, please clarify.
h = sqrt(15^2 − 6^2) = sqrt(225 − 36) = sqrt(189) = 3√21 ≈ 13.747.
So a right circular cone with diameter 12 and slant height 15 has height 3√21 (not 14). If you meant something else, please clarify.
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