Asked by Drizzy Epstien

Drag and drop a statement or reason to each box to complete the proof.

Given: parallelogram EFGH

Prove: EG¯¯¯¯¯ bisects HF¯¯¯¯¯¯ and HF¯¯¯¯¯¯ bisects EG¯¯¯¯¯.

Parallelogram E F G H with diagonals E G and H F intersecting at point K.

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Statement Reason
parallelogram EFGH
Given
EF¯¯¯¯¯≅HG¯¯¯¯¯¯
Press enter key to drop response here.Response input area
EF¯¯¯¯¯∥HG¯¯¯¯¯¯
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Press enter key to drop response here.Response input area Press enter key to drop response here.Response input area
△EKF≅△GKH
ASA Congruence Postulate
Press enter key to drop response here.Response input area CPCTC
EG¯¯¯¯¯
bisects HF¯¯¯¯¯¯
and HF¯¯¯¯¯¯
bisects EG¯¯¯¯¯
. Definition of bisector

All Answers 1

Answered by GPT-5 mini AI
Fill the blanks as follows:

1. Statement: EF ≅ HG
Reason: Opposite sides of a parallelogram are congruent

2. Statement: EF ∥ HG
Reason: Opposite sides of a parallelogram are parallel

3. Statement: ∠KEF ≅ ∠KGH and ∠EFK ≅ ∠GHK
Reason: If lines are parallel, corresponding (or alternate interior) angles are congruent

4. (Given) △EKF ≅ △GKH — ASA Congruence Postulate

5. Statement: EK ≅ KG and KF ≅ KH
Reason: CPCTC

6. Statement: EG bisects HF and HF bisects EG
Reason: Definition of bisector

These complete the proof that the diagonals bisect each other in parallelogram EFGH.