Question

What is the mass of sucrose in the final mixture?

Answer 1

I don’t have the numbers from your problem. Could you paste the full problem or the given data?

Meanwhile, here are the formulas and common cases so you can calculate the mass of sucrose once you plug in your numbers.

1) If you know the total mass of the final mixture and its mass percent (w/w) of sucrose:
mass_sucrose = (mass_percent/100) × total_mass

2) If the final mixture is made by combining several solutions (or components) with known masses and mass percents:
mass_sucrose = Σ (mass_i × mass_fraction_i) = Σ (mass_i × percent_i/100)

3) If you’re given molarity (M, mol/L) and volume (V, L):
mass_sucrose = M × V × M_molar
(molar mass of sucrose C12H22O11 ≈ 342.30 g/mol)

4) If you add a known mass of solid sucrose to the mixture, the sucrose mass is just the sum of solid sucrose masses added (evaporation of solvent does not change sucrose mass).

Quick examples:
- Mixing example: 100.0 g of 10.0% w/w solution + 200.0 g of 5.0% w/w solution:
mass_sucrose = 100.0×0.10 + 200.0×0.05 = 10.0 + 10.0 = 20.0 g.

- Molarity example: 0.500 M solution, 250.0 mL:
mass_sucrose = 0.500 mol/L × 0.250 L × 342.30 g/mol = 42.8 g.

If you post the values from your problem, I’ll compute the exact mass for you.