Asked by j
What is the total volume of the final mixture?
mL
All Answers 1
Answered by
GPT-5 mini
AI
I don't have the numbers from your problem — can you paste the full question?
General rules you can use:
- If you're simply mixing liquids and volumes are given directly, the total volume is the sum:
total volume = V1 + V2 + ... (in mL).
- If you're given masses and densities, convert each to volume first:
Vi = massi / densityi, then total volume = sum Vi.
- If you mix solutions of known concentrations and volumes and need the final concentration, total volume is still Vtotal = V1 + V2 + ...; final concentration = (n1 + n2 + ...)/Vtotal where ni = CiVi (moles).
- If you are asked to find the volume needed to reach a target concentration Cfinal from one or more solutions, use:
Vfinal = (sum CiVi) / Cfinal (when CiVi are total moles from added solutions and you solve for Vfinal).
Example: mixing 25.0 mL and 15.0 mL → total = 40.0 mL.
Example for concentrations: 100 mL of 0.60 M + 50 mL of 0.20 M → total moles = 0.60·0.100 + 0.20·0.050 = 0.06 + 0.01 = 0.07 mol; total volume = 150 mL; final [ ] = 0.07 mol / 0.150 L = 0.467 M.
Give the numbers from your problem and I’ll compute the total volume (in mL) for you.
General rules you can use:
- If you're simply mixing liquids and volumes are given directly, the total volume is the sum:
total volume = V1 + V2 + ... (in mL).
- If you're given masses and densities, convert each to volume first:
Vi = massi / densityi, then total volume = sum Vi.
- If you mix solutions of known concentrations and volumes and need the final concentration, total volume is still Vtotal = V1 + V2 + ...; final concentration = (n1 + n2 + ...)/Vtotal where ni = CiVi (moles).
- If you are asked to find the volume needed to reach a target concentration Cfinal from one or more solutions, use:
Vfinal = (sum CiVi) / Cfinal (when CiVi are total moles from added solutions and you solve for Vfinal).
Example: mixing 25.0 mL and 15.0 mL → total = 40.0 mL.
Example for concentrations: 100 mL of 0.60 M + 50 mL of 0.20 M → total moles = 0.60·0.100 + 0.20·0.050 = 0.06 + 0.01 = 0.07 mol; total volume = 150 mL; final [ ] = 0.07 mol / 0.150 L = 0.467 M.
Give the numbers from your problem and I’ll compute the total volume (in mL) for you.
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