Question

Find center, vertices, co-vertices and foci for the following;
(x-3(^2/49 + (y-4)^2/4 = 1
Center would be (3,4)
A=7
b=2
Vertices would be found this way:
(h+-a,k)
(3-7,4)
(3+7,4)
Vertices = (-4,4)
(10,4)
Co-vertices
(h,k+-b)
(3,4-2)
(3,4+2)
Co-vertices=(3,2)
(3,6)

If ound "c" by 49-4 = c^2
45=c^2
3sqrt(5)=c
6.7=c
Foci =(h+-c,k)
(3-6.7,4)
(3+6.7,4)
Co-vertices=(-3.7,4)
(9.7,4)or left in radical it would be: 3- (3sqrt5),4
3+(3sqrt5),4

Answer 1

I agree with all your answers.

Answer 2

Thank you