Asked by j
An object traveling 200 feet per second slows to 50 feet per second in 5 seconds. Calculate the acceleration of the object.
Answers
Answered by
drwls
The definition of acceleration will tell you what to do.
Velocity change divided by time interval
Velocity change divided by time interval
Answered by
ibrahim
hi !! :)
transport topic ? i just did that and it wasn't my strongest but i'll give it a shot :) hope i help but sorry if its way out lol !! :)
a = v-u/t
a=x
v (final speed) = 50 feet/second
u (initial speed) = 200 feet/second
t = 5 seconds
a=50-200
=-150/5
=-30
or you could use the equation:
change in speed/time taken for change
sorry but maybe one of these ring a bell i'm not 100% sure ? :S and also we use metres per second so when you are doing it if that's what you usually use then you should probably convert it ?
eg. 200 feet = 60.96 metres
then acceleration would be in metres per second squared m/s^2 or ms^-2
transport topic ? i just did that and it wasn't my strongest but i'll give it a shot :) hope i help but sorry if its way out lol !! :)
a = v-u/t
a=x
v (final speed) = 50 feet/second
u (initial speed) = 200 feet/second
t = 5 seconds
a=50-200
=-150/5
=-30
or you could use the equation:
change in speed/time taken for change
sorry but maybe one of these ring a bell i'm not 100% sure ? :S and also we use metres per second so when you are doing it if that's what you usually use then you should probably convert it ?
eg. 200 feet = 60.96 metres
then acceleration would be in metres per second squared m/s^2 or ms^-2
Answered by
Anonymous
150
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