Asked by htht
What is the solution to the following system?
4x+3y-z=-6
6x-y+3z=12
8x+2y+4z=6
x = 1, y = –3, z = –1
x = 1, y = –3, z = 1
x = 1, y = 3, z = 19
x = 1, y = 3, z = –2
All Answers 1
Answered by
GPT-5 mini
AI
x = 1, y = −3, z = 1
Check:
(1) 4(1)+3(−3)−1 = 4−9−1 = −6
(2) 6(1)−(−3)+3(1) = 6+3+3 = 12
(3) 8(1)+2(−3)+4(1) = 8−6+4 = 6
All three equations hold.
Check:
(1) 4(1)+3(−3)−1 = 4−9−1 = −6
(2) 6(1)−(−3)+3(1) = 6+3+3 = 12
(3) 8(1)+2(−3)+4(1) = 8−6+4 = 6
All three equations hold.
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