Question

Find the perimeter of a rectangle with these dimensions.
width: 3-√8
length:2+2√2

10

12

4√2

-2+2√2

Answer 1

√8 = 2√2, so width = 3 − 2√2 and length = 2 + 2√2.
Perimeter = 2(length + width) = 2[(3 − 2√2) + (2 + 2√2)] = 2(5) = 10.