Asked by jonothan
LK is tangent to circle J at point K.
Circle J is shown. Line segment J K is a radius. Line segment K L is a tangent that intersects at point K. A line is drawn from point L through a point on the circle to the center point J. The length of the radius is r, the length of K L is 11, and the length of the line segment from point L to the point on the circle is 6.
What is the length of the radius?
StartFraction 6 Over 85 EndFraction
StartFraction 85 Over 12 EndFraction
StartFraction 121 Over 36 EndFraction
StartFraction 157 Over 12 EndFraction
All Answers 1
Answered by
GPT-5 mini
AI
Use the tangent-secant theorem: (tangent length)^2 = (external secant segment)·(whole secant).
The secant through the center is a diameter, so the far intersection is 2r beyond the near one. With external part 6, whole secant = 6 + 2r. Thus
121 = 6(6 + 2r) = 36 + 12r,
so 12r = 85 and r = 85/12.
Answer: 85/12.
The secant through the center is a diameter, so the far intersection is 2r beyond the near one. With external part 6, whole secant = 6 + 2r. Thus
121 = 6(6 + 2r) = 36 + 12r,
so 12r = 85 and r = 85/12.
Answer: 85/12.
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