Asked by ny
Analyze the graph to describe the solubility of barium nitrate, Ba(NOes001-1.jpg)es001-2.jpg.
At 60°C,
must be added to 1 L of water to make a saturated solution.
At 25°C, the solubility is about
.
A solution that contains 600 g Ba(NOes003-1.jpg)es003-2.jpg in
3 L of H2O at 70°C is
.
For a solution that contains 300 g Ba(NOes004-1.jpg)es004-2.jpg in 3 L of H2O at 60°C to become saturated,
g solute must be added.
All Answers 1
Answered by
GPT-5 mini
AI
I can’t see the images you attached. Please either upload the solubility graph (or the image files) again or tell me the solubility values read from the graph at 25°C, 60°C and 70°C (usually given in g solute per 100 g H2O). Once I have those numbers I’ll give the four requested answers.
Meanwhile, here are the steps I’ll use so you can check or transcribe quickly:
1. Interpretation
- I assume the graph gives solubility S(T) in g Ba(NO3)2 per 100 g H2O at temperature T.
2. Conversions
- 1 L water ≈ 1000 g water.
- 3 L water ≈ 3000 g water.
- Amount of solute that will dissolve in V L water at temperature T = S(T) × (mass of water/100) = S(T) × (1000·V / 100) = S(T) × 10·V (for V in L).
3. Answers you asked for
- “At 60°C, _____ must be added to 1 L of water to make a saturated solution.”
-> Calculate: mass_saturated_1L = S(60°C) × (1000/100) = 10 × S(60°C) g. That is the grams to add to 1 L to reach saturation at 60°C.
- “At 25°C, the solubility is about _____.”
-> That is simply S(25°C) from the graph (in g per 100 g H2O). If you want g per L of water, multiply by 10.
- “A solution that contains 600 g Ba(NO3)2 in 3 L of H2O at 70°C is _____.”
-> Compute max dissolve at 70°C: max70 = S(70°C) × (3000/100) = 30 × S(70°C) g.
- If 600 < max70 → unsaturated.
- If 600 = max70 → saturated.
- If 600 > max70 → supersaturated (or will precipitate until only max70 remains).
- “For a solution that contains 300 g Ba(NO3)2 in 3 L of H2O at 60°C to become saturated, ____ g solute must be added.”
-> Compute max60 = S(60°C) × 30 (g). Required to add = max60 − 300 (if positive). If negative or zero, no addition needed (it’s already saturated or supersaturated).
If you upload the graph or give me S(25°C), S(60°C), and S(70°C), I’ll plug in the numbers and give the four specific numeric answers.
Meanwhile, here are the steps I’ll use so you can check or transcribe quickly:
1. Interpretation
- I assume the graph gives solubility S(T) in g Ba(NO3)2 per 100 g H2O at temperature T.
2. Conversions
- 1 L water ≈ 1000 g water.
- 3 L water ≈ 3000 g water.
- Amount of solute that will dissolve in V L water at temperature T = S(T) × (mass of water/100) = S(T) × (1000·V / 100) = S(T) × 10·V (for V in L).
3. Answers you asked for
- “At 60°C, _____ must be added to 1 L of water to make a saturated solution.”
-> Calculate: mass_saturated_1L = S(60°C) × (1000/100) = 10 × S(60°C) g. That is the grams to add to 1 L to reach saturation at 60°C.
- “At 25°C, the solubility is about _____.”
-> That is simply S(25°C) from the graph (in g per 100 g H2O). If you want g per L of water, multiply by 10.
- “A solution that contains 600 g Ba(NO3)2 in 3 L of H2O at 70°C is _____.”
-> Compute max dissolve at 70°C: max70 = S(70°C) × (3000/100) = 30 × S(70°C) g.
- If 600 < max70 → unsaturated.
- If 600 = max70 → saturated.
- If 600 > max70 → supersaturated (or will precipitate until only max70 remains).
- “For a solution that contains 300 g Ba(NO3)2 in 3 L of H2O at 60°C to become saturated, ____ g solute must be added.”
-> Compute max60 = S(60°C) × 30 (g). Required to add = max60 − 300 (if positive). If negative or zero, no addition needed (it’s already saturated or supersaturated).
If you upload the graph or give me S(25°C), S(60°C), and S(70°C), I’ll plug in the numbers and give the four specific numeric answers.
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