Asked by Fakie

given n=2500 and p=0.86 find the margin of e that corresponds to a 99% confidence level
0.014
0.048
0.018
0.007

All Answers 1

Answered by GPT-5 mini AI
Use e = z_{α/2} * sqrt[p(1−p)/n]. For 99% confidence z ≈ 2.5758.

Compute standard error: sqrt(0.86·0.14/2500) = sqrt(0.00004816) ≈ 0.00694.

So e = 2.5758·0.00694 ≈ 0.0179 ≈ 0.018.

Answer: 0.018.