Question

Solve the system of two linear equations.
−3x−4y=−23

3x−5y=5
(1 point)
Responses

(−5,−2)

left parenthesis negative 5 comma negative 2 right parenthesis

(−5, 2)

left parenthesis negative 5 comma 2 right parenthesis

(5,−2)

left parenthesis 5 comma negative 2 right parenthesis

(5, 2)

Answer 1

Add the equations: (-3x−4y) + (3x−5y) = −23 + 5 ⇒ −9y = −18 ⇒ y = 2.
Substitute y = 2 into 3x − 5y = 5: 3x − 10 = 5 ⇒ 3x = 15 ⇒ x = 5.

Solution: (5, 2).