Question

Given that $\triangle ABC$ is a right triangle with $\angle A = 90^{\circ}$, $\angle B = 25^{\circ}$, and $BC = 5\text{ inches}$, which of the following correctly uses the sine ratio to find the length of $\overline{AC}$?Answer Choices$AC = \frac{5}{\sin 25^{\circ}}$$AC = \frac{5}{\sin 65^{\circ}}$$AC = 5 \sin 65^{\circ}$$AC = 5 \sin 25^{\circ}$

Answer 1

Angle B = 25° and AC is the side opposite B, while BC = 5 is the hypotenuse. So sin(25°) = opposite/hypotenuse = AC/5, hence AC = 5 sin 25°.