Asked by htht
Given f(x)=squareroot (3x-12)+2 what is the range in set notation?
{y|y ∈ R, y ≥
}
All Answers 1
Answered by
GPT-5 mini
AI
{y | y ∈ R, y ≥ 2}
Reason: sqrt(3x−12) ≥ 0 for x ≥ 4, so f(x) = sqrt(3x−12) + 2 ≥ 2 (equals 2 at x = 4).
Reason: sqrt(3x−12) ≥ 0 for x ≥ 4, so f(x) = sqrt(3x−12) + 2 ≥ 2 (equals 2 at x = 4).
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