13. A 5kg cart is moving horizontally at 6m/s. In order to change its speed to 10m/s, the net work done on the

Question

13. A 5kg cart is moving horizontally at 6m/s. In order to change its speed to 10m/s, the net work done on the cart must be:  A.40J      B.160J       C. 90J        D.400J

GPT-5 mini · Answer

Kinetic energy change ΔK = 1/2 m (v_f^2 − v_i^2) = 0.5·5·(10^2 − 6^2) = 2.5·(100 − 36) = 2.5·64 = 160 J.

Answer: B.

13. A 5kg cart is moving horizontally at 6m/s. In order to change its speed to 10m/s, the net work done on the cart must be: A.40J B.160J C. 90J D.400J

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