Question

Xavier is looking up at a building that is 123 meters away from him, at an angle of elevation of 52°
. What is the building’s height above Xavier’s eye level, x, and the distance between Xavier and the top of the building, y? (1 point)
Responses

x=199.79 m
and y=157.43 m

x equals 199.79 m and y equals 157.43 m

x=96.1 m
and y=156.09 m

x equals 96.1 m and y equals 156.09 m

x=157.43 m
and y=199.79 m

x equals 157.43 m and y equals 199.79 m

x=157.43 m
and y=98.26 m

Answer 1

Use trig with the horizontal distance = 123 m and angle = 52°.

x = 123·tan(52°) ≈ 123·1.27994 ≈ 157.43 m
y = 123 / cos(52°) ≈ 123·1.62349 ≈ 199.79 m

So x = 157.43 m and y = 199.79 m.