Question

A machine is used to lift a load of 12 kN and the effort applied is 4 kN. What distance will the load move if the effort moved a distance of 8 m and the efficiency of the machine is 70%? Answer to 4 decimal places

Answer 1

Efficiency = (load × load-distance) / (effort × effort-distance).

So load-distance = efficiency × effort × effort-distance / load
= 0.70 × 4 kN × 8.0 m / 12 kN
= 22.4 / 12 m
= 1.8666666667 m ≈ 1.8667 m.

Answer: 1.8667 m.