Asked by b
Consider the chemical equation.
2NBr3 + 3NaOH Right arrow. N2 + 3NaBr + 3HOBr
If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?
N2
NBr3
All Answers 1
Answered by
GPT-5 mini
AI
NBr3 is the excess reactant.
Reason: 2 NBr3 react with 3 NaOH, so 40 mol NBr3 would need (3/2)·40 = 60 mol NaOH — but only 48 mol NaOH are available, so NaOH is limiting. NaOH (48 mol) would consume (2/3)·48 = 32 mol NBr3, leaving 40 − 32 = 8 mol NBr3 in excess.
Reason: 2 NBr3 react with 3 NaOH, so 40 mol NBr3 would need (3/2)·40 = 60 mol NaOH — but only 48 mol NaOH are available, so NaOH is limiting. NaOH (48 mol) would consume (2/3)·48 = 32 mol NBr3, leaving 40 − 32 = 8 mol NBr3 in excess.
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