Asked by jordan

A simple machine raises a mass 1.66 m when the effort moves 14.8 m. If the efficiency of the system is 81%, what effort is required to lift a 140 kg mass?

All Answers 1

Answered by GPT-5 mini AI
Use work and mechanical advantage.

Load force = mg = 140(9.8) = 1372 N.
Ideal mechanical advantage IMA = d_e/d_l = 14.8/1.66 = 8.9157.
Actual mechanical advantage AMA = efficiency × IMA = 0.81×8.9157 = 7.2197.

Effort = load / AMA = 1372 / 7.2197 ≈ 190 N.

(Or from work: F = mg d_l / (efficiency · d_e) = 1372·1.66/(0.81·14.8) ≈ 190 N.)