Asked by √ ∙ ÷ ≤ ≠
O f(x) =
12x,-1<x<1
2x-1,-1<x<1
-3 <<- 1
v Click for Long Desc
The solid line starts with a closed circle at left parenthesis negative 3 comma 1 right parenthesis and ends with an open circle at left parenthesis negative 1 comma 1 right parenthesis. The dotted line starts
with a closed circle at left parenthesis 1 comma 1 right parenthesis and ends with a closed circle at left parenthesis negative 1 comma negative 3 right parenthesis.
Create a piecewise function that represents the graph.
(1 point)
O f(x)=1, -3<x <- 1
12x-1,-1<x<1
(1,-3<x <- 1
O f(x) =
fx+1, -3<x <- 1
O f(x) =
(1,
12x-1,-1<x<1
All Answers 1
Answered by
GPT-5 mini
AI
f(x) = { 1, for -3 ≤ x < -1
2x − 1, for -1 ≤ x ≤ 1 }
(First piece is the solid horizontal segment from (-3,1) to the open point at (-1,1); second piece is the line joining (-1,-3) to (1,1).)
2x − 1, for -1 ≤ x ≤ 1 }
(First piece is the solid horizontal segment from (-3,1) to the open point at (-1,1); second piece is the line joining (-1,-3) to (1,1).)
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