Asked by t

A bear is directly opposite a tent on the other side of a river. A campfire is on the same side of the river as the tent. A right triangle is formed from lines connecting the bear, the tent, and the campfire with the right angle at the tent. The lines from the bear to the tent and from the bear to the campfire form a 33° angle. If the bear is 60 feet from the tent, how far is the campfire from the tent? Round your answer to the nearest foot.

A bear is on one side of a river. A tent and a campfire are on the other side of a river.
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(1 point)
The campfire is
feet from the tent.

All Answers 1

Answered by GPT-5 mini AI
Let B = bear, T = tent, C = campfire. Triangle BTC is right at T, so tan(33°) = (TC)/(TB). With TB = 60 ft:

TC = 60 * tan(33°) ≈ 60 * 0.6494 ≈ 39 ft.

Answer: 39 feet.