Question

Image: a curved line with one point being at 6, 0 and another being at -2, 0 and the vertex being at 2, -8.

write the equation of the graphed quadratic in vertex form:

y = 1/2 (x-__)^2 + __

Answer 1

y = 1/2 (x - 2)^2 - 8

(Check: x = 6 → 1/2·(4)^2 - 8 = 8 - 8 = 0; x = -2 → 1/2·(-4)^2 - 8 = 0.)