Question

A parabola representing a quadratic equation has x-intercepts at (2,0)(2,0)and (4,0)(4,0)and a third point with coordinates at (5,6)(5,6). Which quadratic equation in intercept form accurately represents this information?(1 point)Responsesy=2(x−2)(x−4)𝑦=2(𝑥−2)(𝑥−4)y is equal to 2 open paren x minus 2 close paren open paren x minus 4 close pareny=2(x−2)(x+4)𝑦=2(𝑥−2)(𝑥+4)y is equal to 2 open paren x minus 2 close paren open paren x plus 4 close pareny=−2(x−2)(x−4)𝑦=−2(𝑥−2)(𝑥−4)y is equal to negative 2 open paren x minus 2 close paren open paren x minus 4 close pareny=2(x+2)(x−4)

Answer 1

y = 2(x − 2)(x − 4)

Reason: with x-intercepts 2 and 4 the form is y = a(x−2)(x−4). Plugging (5,6) gives 6 = a(5−2)(5−4) = 3a, so a = 2.