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QuestionWhat is the vertex of the parabola given by the equation y=4(x+2.5)2𝑦=4(𝑥+2.5)2? If the response contains a decimal value, include it to the tenths place.(1 point)(,)Check answer
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The vertex is at (-2.5, 0.0).
Explanation: y = 4(x + 2.5)^2 is in vertex form y = a(x - h)^2 + k with h = -2.5 and k = 0.
Explanation: y = 4(x + 2.5)^2 is in vertex form y = a(x - h)^2 + k with h = -2.5 and k = 0.
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