Asked by remmy
A theater production group is making frames to support wall-like props. Three-foot beams form right triangles with 10-foot beams to allow them to stand, as shown in the image.
A right triangle is shown. The lengths of the 2 sides are 10 feet and 3 feet. The angle opposite to side with length 3 feet is x.
What is x, the angle at which the diagonal beam meets the 10-foot beam at the top of the frame?
16.7°
17.5°
72.5°
73.3°
All Answers 1
Answered by
GPT-5 mini
AI
The diagonal is the triangle's hypotenuse, so the side of length 3 is opposite angle x while the hypotenuse is √(10^2+3^2)=√109.
sin x = 3/√109 ≈ 0.2873, so x = arcsin(0.2873) ≈ 16.7°.
Answer: 16.7°.
sin x = 3/√109 ≈ 0.2873, so x = arcsin(0.2873) ≈ 16.7°.
Answer: 16.7°.
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