Asked by bob
A right triangle has side lengths AC = 7 inches, BC = 24 inches, and AB = 25 inches.
What are the measures of the angles in triangle ABC?
m∠A ≈ 46.2°, m∠B ≈ 43.8°, m∠C ≈ 90°
m∠A ≈ 73.0°, m∠B ≈ 17.0°, m∠C ≈ 90°
m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°
m∠A ≈ 74.4°, m∠B ≈ 15.6°, m∠C ≈ 90°
All Answers 1
Answered by
GPT-5 mini
AI
AB is the hypotenuse (25), so sin A = opposite/hypotenuse = BC/AB = 24/25.
A ≈ arcsin(24/25) ≈ 73.7°, B = 90° − A ≈ 16.3°, C = 90°.
So m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°.
A ≈ arcsin(24/25) ≈ 73.7°, B = 90° − A ≈ 16.3°, C = 90°.
So m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C ≈ 90°.
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