Question

Which of the following is the graph of y = negative 4 StartRoot x EndRoot?
On a coordinate plane, an absolute value curve opens down and to the right in quadrant 1 and starts at (0, 0).
On a coordinate plane, an absolute value curve opens down and to the left in quadrant 2 and starts at (0, 0).
On a coordinate plane, an absolute value curve opens up and to the right in quadrant 4 and starts at (0, 0). It goes through (5, negative 2).
On a coordinate plane, an absolute value curve opens up and to the right in quadrant 4 and starts at (0, 0). It goes through (5, negative 9).

Answer 1

y = -4√x has domain x ≥ 0 and values y ≤ 0, so the graph starts at (0,0) and goes down and to the right (into quadrant IV). Evaluate at x = 5: y = -4√5 ≈ -8.944, which is closest to -9. Therefore the fourth option (starts at (0,0), in quadrant IV, goes through (5, −9)) is the correct choice.