Question

What is the domain of the square root function graphed below?

On a coordinate plane, a curve open up to the right in quadrant 4. It starts at (0, negative 1) and goes through (1, negative 2) and (4, negative 3).
x less-than-or-equal-to negative 1
x greater-than-or-equal-to negative 1
x less-than-or-equal-to 0
x greater-than-or-equal-to 0

Answer 1

x ≥ 0

Reason: the square-root curve has its left endpoint at x = 0 (point (0, −1)) and opens to the right, so all x-values on the graph are 0 or greater.